(1/128)^-5x+8=32^-x+3

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Solution for (1/128)^-5x+8=32^-x+3 equation: 



(1/128)^-5x+8=32^-x+3

We move all terms to the left:

(1/128)^-5x+8-(32^-x+3)=0

We add all the numbers together, and all the variables

-5x-(32^-x+3)+8+(+1/128)^=0

We get rid of parentheses

-5x+x-3+8-32^+(+1/128)^=0

We multiply all the terms by the denominator


-5x*128)^+x*128)^-3*128)^+8*128)^-32^*128)^+(+1=0

Wy multiply elements

-171798691840x^6=0

We do not support expression: x^6

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